y=7(y^2+5y+6)

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Solution for y=7(y^2+5y+6) equation:



y=7(y^2+5y+6)
We move all terms to the left:
y-(7(y^2+5y+6))=0
We calculate terms in parentheses: -(7(y^2+5y+6)), so:
7(y^2+5y+6)
We multiply parentheses
7y^2+35y+42
Back to the equation:
-(7y^2+35y+42)
We get rid of parentheses
-7y^2+y-35y-42=0
We add all the numbers together, and all the variables
-7y^2-34y-42=0
a = -7; b = -34; c = -42;
Δ = b2-4ac
Δ = -342-4·(-7)·(-42)
Δ = -20
Delta is less than zero, so there is no solution for the equation

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